3[x-(2+3x)]=2x+2

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Solution for 3[x-(2+3x)]=2x+2 equation:


Simplifying
3[x + -1(2 + 3x)] = 2x + 2
3[x + (2 * -1 + 3x * -1)] = 2x + 2
3[x + (-2 + -3x)] = 2x + 2

Reorder the terms:
3[-2 + x + -3x] = 2x + 2

Combine like terms: x + -3x = -2x
3[-2 + -2x] = 2x + 2
[-2 * 3 + -2x * 3] = 2x + 2
[-6 + -6x] = 2x + 2

Reorder the terms:
-6 + -6x = 2 + 2x

Solving
-6 + -6x = 2 + 2x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-2x' to each side of the equation.
-6 + -6x + -2x = 2 + 2x + -2x

Combine like terms: -6x + -2x = -8x
-6 + -8x = 2 + 2x + -2x

Combine like terms: 2x + -2x = 0
-6 + -8x = 2 + 0
-6 + -8x = 2

Add '6' to each side of the equation.
-6 + 6 + -8x = 2 + 6

Combine like terms: -6 + 6 = 0
0 + -8x = 2 + 6
-8x = 2 + 6

Combine like terms: 2 + 6 = 8
-8x = 8

Divide each side by '-8'.
x = -1

Simplifying
x = -1

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